((8-x)^3(7x-6))/(x^3+27)

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Solution for ((8-x)^3(7x-6))/(x^3+27) equation: 


D( x )

x^3+27 = 0

x^3+27 = 0

x^3+27 = 0

1*x^3 = -27 // : 1

x^3 = -27

x^3 = -27 // ^ 1/3

x = -3

x in (-oo:-3) U (-3:+oo)

((8-x)^3*(7*x-6))/(x^3+27) = 0

( 7*x-6 )

7*x-6 = 0 // + 6

7*x = 6 // : 7

x = 6/7

( 8-x )

8-x = 0 // - 8

-x = -8 // * -1

x = 8

x in { 6/7, 8, 8, 8 }

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